- categories: Code, Interview Question, leetcode, Medium
- source: https://leetcode.com/problems/simplify-path
- topics: String Manipulation, Stack
You are given an absolute path for a Unix-style file system, which always begins with a slash '/'
. Your task is to transform this absolute path into its simplified canonical path.
The rules of a Unix-style file system are as follows:
- A single period
'.'
represents the current directory. - A double period
'..'
represents the previous/parent directory. - Multiple consecutive slashes such as
'//'
and'///'
are treated as a single slash'/'
. - Any sequence of periods that does not match the rules above should be treated as a valid directory or file name. For example,
'...'
and'....'
are valid directory or file names.
The simplified canonical path should follow these rules:
- The path must start with a single slash
'/'
. - Directories within the path must be separated by exactly one slash
'/'
. - The path must not end with a slash
'/'
, unless it is the root directory. - The path must not have any single or double periods (
'.'
and'..'
) used to denote current or parent directories.
Return the simplified canonical path.
Idea:
Use stack
class Solution:
def simplifyPath(self, path: str) -> str:
stack = deque()
for s in path.split("/"):
if not s:
continue
if s == "..":
if stack:
stack.pop()
continue
if s == ".":
continue
stack.append(s)
return "/" + "/".join(stack)