- categories: Code, Interview Question, leetcode, Medium
- source: https://leetcode.com/problems/find-eventual-safe-states
- topics: Graph, Recursion, DFS
Description
There is a directed graph of n nodes with each node labeled from 0 to n - 1. The graph is represented by a 0-indexed 2D integer array graph where graph[i] is an integer array of nodes adjacent to node i, meaning there is an edge from node i to each node in graph[i].
A node is a terminal node if there are no outgoing edges. A node is a safe node if every possible path starting from that node leads to a terminal node (or another safe node).
Return an array containing all the safe nodes of the graph. The answer should be sorted in ascending order.
Idea
- Straightforward DFS with memoization
Code
class Solution:
def eventualSafeNodes(self, graph: List[List[int]]) -> List[int]:
visited = set()
@cache
def is_safe(i):
if not graph[i]:
return True
if i in visited:
return False
visited.add(i)
for adj in graph[i]:
if not is_safe(adj):
return False
visited.remove(i)
return True
return [i for i in range(len(graph)) if is_safe(i)]