- categories: Code, Interview Question, leetcode, Easy
- source: https://leetcode.com/problems/roman-to-integer/
- topics: String Manipulation
Roman numerals are represented by seven different symbols: I
, V
, X
, L
, C
, D
and M
.
Symbol Value I 1 V 5 X 10 L 50 C 100 D 500 M 1000
For example, 2
is written as II
in Roman numeral, just two ones added together. 12
is written as XII
, which is simply X + II
. The number 27
is written as XXVII
, which is XX + V + II
.
Roman numerals are usually written largest to smallest from left to right. However, the numeral for four is not IIII
. Instead, the number four is written as IV
. Because the one is before the five we subtract it making four. The same principle applies to the number nine, which is written as IX
. There are six instances where subtraction is used:
I
can be placed beforeV
(5) andX
(10) to make 4 and 9.X
can be placed beforeL
(50) andC
(100) to make 40 and 90.C
can be placed beforeD
(500) andM
(1000) to make 400 and 900.
Given a roman numeral, convert it to an integer.
class Solution:
def romanToInt(self, s: str) -> int:
symbols = { "I": 1,
"IV":4,
"V": 5,
"IX":9,
"X": 10,
"XL":40,
"L": 50,
"XC":90,
"C": 100,
"CD": 400,
"D": 500,
"CM": 900,
"M": 1000
}
ans = 0
i = 0
while i < len(s):
if s[i:i+2] in symbols:
ans += symbols[s[i:i+2]]
i += 2
else:
ans += symbols[s[i]]
i += 1
return ans