- categories: Code, Interview Question, leetcode, Medium
- source: https://leetcode.com/problems/binary-tree-level-order-traversal
- topics: Tree, BFS
Given the root
of a binary tree, return the level order traversal of its nodes’ values. (i.e., from left to right, level by level).
Idea
BFS
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, val=0, left=None, right=None):
# self.val = val
# self.left = left
# self.right = right
class Solution:
def levelOrder(self, root: Optional[TreeNode]) -> List[List[int]]:
if not root:
return []
ans = []
d = deque([root])
while d:
level_nodes = []
for _ in range(len(d)):
element = d.popleft()
level_nodes.append(element.val)
if element.left:
d.append(element.left)
if element.right:
d.append(element.right)
ans.append(level_nodes)
return ans